The detailed process of Interger creating objects

The detailed process of Interger creating objects

Write the execution results of the following three pieces of code:

Code snippet 1

Integer integer1 = 100;
Integer integer2 = 100;
System.out.println(integer1 == integer2);

Code snippet 2

Integer integer3 = 1000;
Integer integer4 = 1000;
System.out.println(integer3 == integer4);

Code snippet 3

Integer integer5 = new Integer(100);
Integer integer6 = new Integer(100);
System.out.println(integer5 == integer6);

operation result:

 1 true
 2 false
 3 false

In code snippet 1 , 100 is within the bytevalue range, and integer1an Integerobject is created and saved in the byteconstant pool when it is created , and integer2the value is integer1equal to and the object in the constant pool is reused directly. Therefore, integer1and integer2is the same object.

In code snippet 2 , 1000 is not in the bytevalue range, and the object is recreated every time the value is assigned. Therefore, integer3and integer4are two different objects.

In code snippet 3 , because the keyword is used new, no matter whether the value is within the bytevalue range, newan object is created in the heap memory every time . Therefore, integer5and integer6are two different objects.

Note: Under normal circumstances, what is int hashCode = object.hashCode();returned is the memory address of the object, but it hashCode()may be rewritten. Therefore, int hashCode = System.identityHashCode(object);the memory address of the object can be obtained through methods .

Integer the process of creating an object